一本通1104:计算书费(Yibentong 1104: calculating book fees)

1104:计算书费

【题目描述】

下面是一个图书的单价表:

计算概论 28.9元/本

数据结构与算法 32.7元/本

数字逻辑 45.6元/本

C++程序设计教程 78元/本

人工智能 35 元/本

计算机体系结构 86.2元/本

编译原理 27.8元/本

操作系统 43元/本

计算机网络 56元/本

JAVA程序设计 65元/本

给定每种图书购买的数量,编程计算应付的总费用。

【输入】

输入一行,包含10个整数(大于等于0,小于等于100),分别表示购买的《计算概论》、《数据结构与算法》、《数字逻辑》、《C++程序设计教程》、《人工智能》、《计算机体系结构》、《编译原理》、《操作系统》、《计算机网络》、《JAVA程序设计》的数量(以本为单位)。每两个整数用一个空格分开。

【输出】

输出一行,包含一个浮点数f,表示应付的总费用。精确到小数点后一位。

【输入样例】

1 5 8 10 5 1 1 2 3 4

【输出样例】

2140.2代码如下:
#include <stdio.h>
int main()
{
    double price[15]={28.9,32.7,45.6,78,35,86.2,27.8,43,56,65};
    int num[15];
    double sum=0;
    int i;
    
    for(i=0;i<10;i++)
    {
        scanf("%d",&num[i]);
        sum+=num[i]*price[i];
    }
    printf("%.1f\n",sum);
    return 0;
}
————————

1104: calculate book cost

[Title Description]

The following is a unit price table of books:

Introduction to calculation 28.9 yuan / book

Data structure and algorithm 32.7 yuan / book

Digital logic 45.6 yuan / book

C + + programming tutorial 78 yuan / book

Artificial intelligence 35 yuan / book

Computer architecture 86.2 yuan / book

Compilation principle 27.8 yuan / book

Operating system 43 yuan / book

Computer network 56 yuan / book

Java programming 65 yuan / book

Given the quantity of each book purchased, the total cost payable is calculated by programming.

[input]

Enter a line containing 10 integers (greater than or equal to 0 and less than or equal to 100), which respectively represent the number of purchased introduction to computing, data structure and algorithm, digital logic, C + + programming tutorial, artificial intelligence, computer architecture, compilation principle, operating system, computer network and Java programming (in this unit). Every two integers are separated by a space.

[output]

Output a line containing a floating-point number f, representing the total fee payable. Accurate to one decimal place.

[input example]

1 5 8 10 5 1 1 2 3 4

[output example]

2140.2代码如下:
#include <stdio.h>
int main()
{
    double price[15]={28.9,32.7,45.6,78,35,86.2,27.8,43,56,65};
    int num[15];
    double sum=0;
    int i;
    
    for(i=0;i<10;i++)
    {
        scanf("%d",&num[i]);
        sum+=num[i]*price[i];
    }
    printf("%.1f\n",sum);
    return 0;
}