爬,都可以爬(Climb, you can climb)

本文章向大家介绍爬,都可以爬,主要包括爬,都可以爬使用实例、应用技巧、基本知识点总结和需要注意事项,具有一定的参考价值,需要的朋友可以参考一下。

本文章向大家介绍爬,都可以爬,主要包括爬,都可以爬使用实例、应用技巧、基本知识点总结和需要注意事项,具有一定的参考价值,需要的朋友可以参考一下。

\({\Huge\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!\!}\text{让我猜猜 }\LaTeX\text{ 会不会被爬}\)爬不多德勒

然后这里要放一些没有意义的代码增加字数:

using pr=array<int,2>;
struct treap{
	struct node{
		int val,rd;
		int lson,rson;
		int siz;
		node()=default;
		node(int __val){val=__val;rd=rand();lson=0;rson=0;siz=1;};
	}tree[100005];
	int root=0,totn=0;
	void update(int i){
		tree[i].siz=tree[tree[i].lson].siz+tree[tree[i].rson].siz+1;
	}
	int newnode(int val){
		tree[++totn]=node(val);
		return totn;
	}
	pr split_kth(int nw,int kth){ // L subtree.siz=k
		if(!nw){
			return pr({0,0});
		}
		if(kth-tree[tree[nw].lson].siz-1>=0){
			pr tmp=split_kth(tree[nw].rson,kth-tree[tree[nw].lson].siz-1);
			tree[nw].rson=tmp[0];
			update(nw);
			return pr({nw,tmp[1]});
		}else{
			pr tmp=split_kth(tree[nw].lson,kth);
			tree[nw].lson=tmp[1];
			update(nw);
			return pr({tmp[0],nw});
		}
	}
	pr split_kval(int nw,int val){ // L subtree.val<=k
		if(!nw){
			return pr({0,0});
		}
		if(tree[nw].val<=val){
			pr tmp=split_kval(tree[nw].rson,val);
			tree[nw].rson=tmp[0];
			update(nw);
			return pr({nw,tmp[1]});
		}else{
			pr tmp=split_kval(tree[nw].lson,val);
			tree[nw].lson=tmp[1];
			update(nw);
			return pr({tmp[0],nw});
		}
	}
	int merge(int lt,int rt){
		if(!lt||!rt){
			return lt+rt;
		}
		if(tree[lt].rd>tree[rt].rd){
			int tmp=merge(tree[lt].rson,rt);
			tree[lt].rson=tmp;
			update(lt);
			return lt;
		}else{
			int tmp=merge(lt,tree[rt].lson);
			tree[rt].lson=tmp;
			update(rt);
			return rt;
		}
	}
	void insert(int val){
		pr tmp=split_kval(root,val);
		root=merge(tmp[0],merge(newnode(val),tmp[1]));
	}
	void erase(int val){
		pr ltmp=split_kval(root,val-1);
		pr rtmp=split_kth(ltmp[1],1);
		root=merge(ltmp[0],rtmp[1]);
	}
	int getrank(int val){
		pr tmp=split_kval(root,val-1);
		int ret=tree[tmp[0]].siz;
		root=merge(tmp[0],tmp[1]);
		return ret+1;
	}
	int getkth(int kth){
		pr ltmp=split_kth(root,kth-1);
		pr rtmp=split_kth(ltmp[1],1);
		int ret=tree[rtmp[0]].val;
		root=merge(ltmp[0],merge(rtmp[0],rtmp[1]));
		return ret;
	}
	int getpre(int val){
		pr ltmp=split_kval(root,val-1);
		pr rtmp=split_kth(ltmp[0],tree[ltmp[0]].siz-1);
		int ret=tree[rtmp[1]].val;
		root=merge(merge(rtmp[0],rtmp[1]),ltmp[1]);
		return ret;
	}
	int getnxt(int val){
		pr ltmp=split_kval(root,val);
		pr rtmp=split_kth(ltmp[1],1);
		int ret=tree[rtmp[0]].val;
		root=merge(ltmp[0],merge(rtmp[0],rtmp[1]));
		return ret;
	}
}fhq;

下面,我们表演一下传统艺能,粘原文链接!

原文地址:https://www.cnblogs.com/XiEn1847/p/15599315.html

————————

This article introduces you to climb. You can climb, mainly including climbing. You can climb. Use examples, application skills, summary of basic knowledge points and matters needing attention have a certain reference value. Friends in need can refer to it.

This article introduces you to climb. You can climb, mainly including climbing. You can climb. Use examples, application skills, summary of basic knowledge points and matters needing attention have a certain reference value. Friends in need can refer to it.

\”You are in the way \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ you you you you you you you you you you you you you you you you you you you you you you you you you take the way way how how how how how how how how how how how how how how you you you you you you you you you you you you you take take away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away away the what what what you you you you you you you you you you you you you! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \! \!} \ text {let me guess if} \ latex \ text {will be crawled} \) can’t climb much

Then put some meaningless code here to increase the number of words:

using pr=array<int,2>;
struct treap{
	struct node{
		int val,rd;
		int lson,rson;
		int siz;
		node()=default;
		node(int __val){val=__val;rd=rand();lson=0;rson=0;siz=1;};
	}tree[100005];
	int root=0,totn=0;
	void update(int i){
		tree[i].siz=tree[tree[i].lson].siz+tree[tree[i].rson].siz+1;
	}
	int newnode(int val){
		tree[++totn]=node(val);
		return totn;
	}
	pr split_kth(int nw,int kth){ // L subtree.siz=k
		if(!nw){
			return pr({0,0});
		}
		if(kth-tree[tree[nw].lson].siz-1>=0){
			pr tmp=split_kth(tree[nw].rson,kth-tree[tree[nw].lson].siz-1);
			tree[nw].rson=tmp[0];
			update(nw);
			return pr({nw,tmp[1]});
		}else{
			pr tmp=split_kth(tree[nw].lson,kth);
			tree[nw].lson=tmp[1];
			update(nw);
			return pr({tmp[0],nw});
		}
	}
	pr split_kval(int nw,int val){ // L subtree.val<=k
		if(!nw){
			return pr({0,0});
		}
		if(tree[nw].val<=val){
			pr tmp=split_kval(tree[nw].rson,val);
			tree[nw].rson=tmp[0];
			update(nw);
			return pr({nw,tmp[1]});
		}else{
			pr tmp=split_kval(tree[nw].lson,val);
			tree[nw].lson=tmp[1];
			update(nw);
			return pr({tmp[0],nw});
		}
	}
	int merge(int lt,int rt){
		if(!lt||!rt){
			return lt+rt;
		}
		if(tree[lt].rd>tree[rt].rd){
			int tmp=merge(tree[lt].rson,rt);
			tree[lt].rson=tmp;
			update(lt);
			return lt;
		}else{
			int tmp=merge(lt,tree[rt].lson);
			tree[rt].lson=tmp;
			update(rt);
			return rt;
		}
	}
	void insert(int val){
		pr tmp=split_kval(root,val);
		root=merge(tmp[0],merge(newnode(val),tmp[1]));
	}
	void erase(int val){
		pr ltmp=split_kval(root,val-1);
		pr rtmp=split_kth(ltmp[1],1);
		root=merge(ltmp[0],rtmp[1]);
	}
	int getrank(int val){
		pr tmp=split_kval(root,val-1);
		int ret=tree[tmp[0]].siz;
		root=merge(tmp[0],tmp[1]);
		return ret+1;
	}
	int getkth(int kth){
		pr ltmp=split_kth(root,kth-1);
		pr rtmp=split_kth(ltmp[1],1);
		int ret=tree[rtmp[0]].val;
		root=merge(ltmp[0],merge(rtmp[0],rtmp[1]));
		return ret;
	}
	int getpre(int val){
		pr ltmp=split_kval(root,val-1);
		pr rtmp=split_kth(ltmp[0],tree[ltmp[0]].siz-1);
		int ret=tree[rtmp[1]].val;
		root=merge(merge(rtmp[0],rtmp[1]),ltmp[1]);
		return ret;
	}
	int getnxt(int val){
		pr ltmp=split_kval(root,val);
		pr rtmp=split_kth(ltmp[1],1);
		int ret=tree[rtmp[0]].val;
		root=merge(ltmp[0],merge(rtmp[0],rtmp[1]));
		return ret;
	}
}fhq;

Next, let’s perform traditional art skills and stick the original link!

原文地址:https://www.cnblogs.com/XiEn1847/p/15599315.html